document.write( "Question 31236: vector A=3i+4j is a vector in xy plane,
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document.write( "vector B is a vector perpendicular to vector A,
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document.write( "what will be the vector C equal to,which has projections 1 and 2 along vectors A and B? \n" );
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Algebra.Com's Answer #17902 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! if vector B is perpendicular to vector A and A is solely in the x-y plane then vector B has to be solely in the z-plane, so its vector is B=ck...some value of k... we do not know where in the z-plane it lies.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, C = 3i+4j+ck\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I think this is what you require.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( "------------------------------------------------------------------ \n" ); document.write( "OK, after your reply, B is also in the xy plane: my mistake, sorry.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "OK, in the xy plane, a.b = 0 for 2 orthogonal vectors.\r \n" ); document.write( "\n" ); document.write( "we have \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, 3x+4y=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, if both terms were 12 and one negative, then we would have zero. So, how about x=4 and y=-3... that would equal zero.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, C = \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is one version of the answer, since the scalar product could also have been: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in which case, B would be \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "either is correct. \n" ); document.write( "Jon \n" ); document.write( " \n" ); document.write( " |