document.write( "Question 244809: (3+4i)(1-2i) \n" ); document.write( "
Algebra.Com's Answer #179006 by MathTherapy(10552)\"\" \"About 
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(3+4i)(1-2i)\r
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\n" ); document.write( "\n" ); document.write( "Foil the binomials:\r
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\n" ); document.write( "\n" ); document.write( "F ------- 3 * 1 = 3\r
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\n" ); document.write( "\n" ); document.write( "O ------- - 2i * + 3 = - 6i\r
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\n" ); document.write( "\n" ); document.write( "I ------- + 4i * 1 = + 4i\r
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\n" ); document.write( "\n" ); document.write( "L ------- + 4i * - 2i = \"-8i%5E2\" = - 8(-1) = + 8\r
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\n" ); document.write( "\n" ); document.write( "Putting them together, we get: 3 - 6i + 4i + 8\r
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\n" ); document.write( "\n" ); document.write( "Combining like terms gives us: \"highlight_green%2811+-+2i%29\"
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