document.write( "Question 244834: A person has quarters, dimes, nickels,and pennies with a total value of $3.86. The number of nickels is twice the number of quarters. The number of quarters is two less than the number of dimes. There are 40 coins in all. Write and solve an equation to find the number of each coin. I have figured out that there are eight quarters, sixteen nickels, ten dimes, and six pennies. I can not figure out how to write an equation for this problem. Can you help me? \n" ); document.write( "
Algebra.Com's Answer #179005 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
we actually need for equations
\n" ); document.write( "n=2q
\n" ); document.write( "q=d-2
\n" ); document.write( "n=2(d-2)=2d-4
\n" ); document.write( "25q+10d+5n+1p=386
\n" ); document.write( "25(d-2)+10d+5(2d-4)+p=386
\n" ); document.write( "25d+10d+10d-50-20+p386
\n" ); document.write( "45d-70+p=386
\n" ); document.write( "p+q+d+n=40
\n" ); document.write( "p+(d-2)+d+2(d-2)=40
\n" ); document.write( "p+d-2+2d-4=40
\n" ); document.write( "p+4d-6=40
\n" ); document.write( "p+4d=46
\n" ); document.write( "p=46-4d
\n" ); document.write( "45d-70+p=386
\n" ); document.write( "45d+p=456
\n" ); document.write( "45d+46-4d=456
\n" ); document.write( "41d=410
\n" ); document.write( "d=10
\n" ); document.write( "q=d-2=8
\n" ); document.write( "n=16
\n" ); document.write( "p=40-10-16-8
\n" ); document.write( "p=40-34=6\r
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