document.write( "Question 244839: \"2%5E%284x%29%2A3%5Ex=100\"
\n" ); document.write( "I don't know where to start on this one.
\n" ); document.write( "I know it should be a log, but don't know how to set it up.
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Algebra.Com's Answer #179004 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2%5E%284x%29%2A3%5Ex=100\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%282%5E%284x%29%2A3%5Ex%29%29=log%2810%2C%28100%29%29\" Take the log of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%282%5E%284x%29%2A3%5Ex%29%29=2\" Evaluate the log base 10 of 100 to get 2.\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%282%5E%284x%29%29%29%2Blog%2810%2C%283%5Ex%29%29=2\" Break up the log using the identity \"log%28b%2C%28A%2AB%29%29=log%28b%2C%28A%29%29%2Blog%28b%2C%28B%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"4x%2Alog%2810%2C%282%29%29%2Bx%2Alog%2810%2C%283%29%29=2\" Pull down the exponents using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%284%2Alog%2810%2C%282%29%29%2Blog%2810%2C%283%29%29%29=2\" Factor out the GCF 'x'\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%2F%284%2Alog%2810%2C%282%29%29%2Blog%2810%2C%283%29%29%29\" Divide both sides by \"4%2Alog%2810%2C%282%29%29%2Blog%2810%2C%283%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%2F%28log%2810%2C%282%5E4%29%29%2Blog%2810%2C%283%29%29%29\" Place the coefficient as the exponent using the identity \"y%2Alog%28b%2C%28x%29%29=log%28b%2C%28x%5Ey%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%2F%28log%2810%2C%2816%29%29%2Blog%2810%2C%283%29%29%29\" Raise 2 to the 4th power to get 16\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%2F%28log%2810%2C%2816%2A3%29%29%29\" Combine the logs using the identity \"log%28b%2C%28A%29%29%2Blog%28b%2C%28B%29%29=log%28b%2C%28A%2AB%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=2%2Flog%2810%2C%2848%29%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=2%2Flog%2810%2C%2848%29%29\" which approximates to \"x=1.18959727\"
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