document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=244830>Question 244830</A>: <I><SPAN STYLE=\"word-break: break-all;\"> finding the depth of a rectangle with p=500ft and width=104ft what is the formula?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179000 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179000\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter (P) of a rectangle is the sum of the two width sides (W) plus the sum of the two depth sides (D).\r<BR>\n" );
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document.write( "That is: P = W+W+L+L = (2*W) + (2*D)\r<BR>\n" );
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document.write( "Substituting for P and W we have: 500 = (2*104) + 2*D <BR>\n" );
document.write( "Simplifying we have: 500 = 208 + 2*D<BR>\n" );
document.write( "Subtract 208 from both sides of the equation we have: 292 = 2*D<BR>\n" );
document.write( "Dividing both sides of the equaation by 2 we have: 146 = D\r<BR>\n" );
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document.write( "In general:\r<BR>\n" );
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document.write( "P = (2+W) + (2*D)<BR>\n" );
document.write( "P-(2*W) = 2*D<BR>\n" );
document.write( "(P-(2*W))/2 = D    </SPAN>\n" );
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