document.write( "Question 244764: \"It took a faster runner 10 seconds longer to run a distance of 1500 feet than it took a slower runner to run a distance of 1000 feet. if the rate of the faster runner was 5 ft/s more than the rate of the slower runner, what was the rate of each?\" \n" ); document.write( "
Algebra.Com's Answer #178978 by ankor@dixie-net.com(22740)\"\" \"About 
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\"It took a faster runner 10 seconds longer to run a distance of 1500 feet than it took a slower runner to run a distance of 1000 feet.
\n" ); document.write( "Let t = time in sec for the faster runner to run 1500 ft
\n" ); document.write( "then
\n" ); document.write( "(t-10) = time of the slower runner to run 1000 ft
\n" ); document.write( ":
\n" ); document.write( "if the rate of the faster runner was 5 ft/s more than the rate of the slower runner, what was the rate of each?\"
\n" ); document.write( ":
\n" ); document.write( "Write a rate equation: Rate = dist/time:
\n" ); document.write( ":
\n" ); document.write( "Fast rate - slow rate = 5 ft/sec
\n" ); document.write( "\"1500%2Ft\" - \"1000%2F%28t-10%29\" = 5
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by t(t-10), results
\n" ); document.write( "1500(t-10) - 1000t = 5t(t-10)
\n" ); document.write( ":
\n" ); document.write( "1500t - 15000 - 1000t = 5t^2 - 50t
\n" ); document.write( ":
\n" ); document.write( "500t - 15000 = 5t^2 - 50t
\n" ); document.write( ":
\n" ); document.write( "0 = 5t^2 - 50t - 500t + 15000
\n" ); document.write( "A quadratic equation
\n" ); document.write( "5t^2 - 550t + 15000 = 0
\n" ); document.write( "Simplify, divide by 5
\n" ); document.write( "t^2 - 110t + 3000 = 0
\n" ); document.write( "Factor to
\n" ); document.write( "(t - 50)(t - 60) = 0
\n" ); document.write( "two solutions
\n" ); document.write( "t = 50 sec
\n" ); document.write( "t = 60 sec
\n" ); document.write( ":
\n" ); document.write( "Assume t = 50
\n" ); document.write( "1500/50 = 30 ft/sec for the fast guy
\n" ); document.write( "and
\n" ); document.write( "1000/40 = 25 ft/sec for the slow guy (5 ft/sec slower)
\n" ); document.write( ":
\n" ); document.write( "You can check the other solution
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