document.write( "Question 244809: (3+4i)(1-2i) \n" ); document.write( "

Algebra.Com's Answer #178973 by richwmiller(17219) $\"\"$ $\"About$

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(3+4i)(1-2i)
\n" ); document.write( "remember that i=sqrt(-1)and that i^2=-1
\n" ); document.write( "use foil
\n" ); document.write( "first term 3*1=3
\n" ); document.write( "outer terms 3*2i=6i
\n" ); document.write( "inner terms 1*4i=4i
\n" ); document.write( "add (6+4)(i)=10i\r
\n" ); document.write( "\n" ); document.write( "last terms 4i*2i=8(-1)=-8
\n" ); document.write( "3+10i-8
\n" ); document.write( "10i-5\r
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