document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31228>Question 31228</A>: <I><SPAN STYLE=\"word-break: break-all;\"> could someone please help me with this equation????\r<BR>\n" );
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document.write( "use elimination to solve:<BR>\n" );
document.write( "6x-y/4=-9<BR>\n" );
document.write( "and 3x+2y=-30 </SPAN>\n" );
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document.write( "First equation : 6x -y/4 = -9<BR>\n" );
document.write( "Second Equation: 3x + 2y = -30\r<BR>\n" );
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document.write( "Solution:\r<BR>\n" );
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document.write( "Step 1: multiply first equation by 8 to eliminate y\r<BR>\n" );
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document.write( "                  8[6x - y/4 = -9]<BR>\n" );
document.write( "                 <BR>\n" );
document.write( "                    48x - 2y = -72 --- eq 3 <BR>\n" );
document.write( "Step 2: Add eq 3 and second equation\r<BR>\n" );
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document.write( "                    48x - 2y = -72 --- eq 3<BR>\n" );
document.write( "                  +  3x + 2y = -30 --- second equation<BR>\n" );
document.write( "                 -------------------<BR>\n" );
document.write( "                    51x + 0  = -102<BR>\n" );
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document.write( "                          51x = -102<BR>\n" );
document.write( "                          ---   ----<BR>\n" );
document.write( "                          51      51\r<BR>\n" );
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document.write( "                            x = -2\r<BR>\n" );
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document.write( "Step 3: substitute the value of x to second equation to find the value of y       <BR>\n" );
document.write( "                 <BR>\n" );
document.write( "             3x + 2y = -30 --- second equation<BR>\n" );
document.write( "             3(-2) + 2y = -30<BR>\n" );
document.write( "               -6 + 2y = -30 --- transpose -6 to the other side of the equation<BR>\n" );
document.write( "                    2y = -30 + 6<BR>\n" );
document.write( "                    2y = -24<BR>\n" );
document.write( "                    --   ---<BR>\n" );
document.write( "                    2     2<BR>\n" );
document.write( "                     y = -12\r<BR>\n" );
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document.write( "Check if the answere is correct substitute the value of x and y to first equation\r<BR>\n" );
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document.write( "            6x - y/4 = -9 --- first equation<BR>\n" );
document.write( "            6(-2) - (-12/4) = -9<BR>\n" );
document.write( "             -12 + 3 = -9<BR>\n" );
document.write( "                   -9 = -9 --- therefore the answere is corre <BR>\n" );
document.write( "Answere:<BR>\n" );
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document.write( "                       x = -2 ; y = -12 </SPAN>\n" );
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