document.write( "Question 244662: the length of a rectangle is 2cm more than four times the width. if the perimeter of the rectangle is 84cm, what are the demensions? \n" ); document.write( "
Algebra.Com's Answer #178907 by richwmiller(17219)\"\" \"About 
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L=length
\n" ); document.write( "W=width
\n" ); document.write( "L=2+4w
\n" ); document.write( "2L+2W=84
\n" ); document.write( "substitute\r
\n" ); document.write( "\n" ); document.write( "2(2+4w)+2W=84
\n" ); document.write( "4+8W+2W=84
\n" ); document.write( "10W=80
\n" ); document.write( "W=8\r
\n" ); document.write( "\n" ); document.write( "2(8)+2L=84
\n" ); document.write( "16+2L=84
\n" ); document.write( "2L=68
\n" ); document.write( "L=34
\n" ); document.write( "check
\n" ); document.write( "4(8)+2=34
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