document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4053>Question 4053</A>: <I><SPAN STYLE=\"word-break: break-all;\"> By walking 3/4th of his usual speed, a man reaches his office 20 minutes later than usual. What is his usual time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1789 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1789\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Let L be the distance, V be his usual speed.<BR>\n" );
document.write( " We have L/(3/4 V) = L/V + 20.\r<BR>\n" );
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document.write( " So, 4/3 * L/V = L/V + 20, <BR>\n" );
document.write( " Or 1/3 * L/V = 20,<BR>\n" );
document.write( " we get L/V = 60 (min)<BR>\n" );
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document.write( " Since V is his usual speed, so T = L/V his usual time for<BR>\n" );
document.write( " him walking from to the office.\r<BR>\n" );
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document.write( " Another way , let T (min) be the usual time, then he spent 4 T/3<BR>\n" );
document.write( " when walking in 3/4 of usual speed. <BR>\n" );
document.write( " Since 4T/3 = T +20, we obtain T = 60 min. \r<BR>\n" );
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document.write( " Kenny<BR>\n" );
document.write( " </SPAN>\n" );
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