document.write( "Question 244635: Find the center and the radius of the circle described by the equation\r
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Algebra.Com's Answer #178893 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Find the center and the radius of the circle described by the equation \r\n" );
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document.write( "\"x%5E2%2By%5E2%2B8x-2y%2B15=0\"\r\n" );
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document.write( "Get the term in \"x\" next to the term in \"x%5E2\"\r\n" );
document.write( "Get the term in \"y\" next to the term in \"y%5E2\"\r\n" );
document.write( "Add \"-15\" to both sides to get the constant on the right:\r\n" );
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document.write( "\"x%5E2%2B8x%2By%5E2-2y=-15\"\r\n" );
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document.write( "Multiply the coefficient of \"x\", which is \"8\" by \"1%2F2\",\r\n" );
document.write( "getting \"4\". Then square \"4\", getting \"16\".  Then add \r\n" );
document.write( "\"16\" to both sides, writing it next to the term in \"x\" on\r\n" );
document.write( "the left.\r\n" );
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document.write( "\"x%5E2%2B8x%2B16%2By%5E2-2y=-15%2B16\"\r\n" );
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document.write( "Multiply the coefficient of \"y\", which is \"-2\" by \"1%2F2\",\r\n" );
document.write( "getting \"-1\". Then square \"-1\", getting \"%22%22%2B1\".  Then add \r\n" );
document.write( "\"%22%22%2B1\" to both sides, writing it next to the term in \"y\" on\r\n" );
document.write( "the left.\r\n" );
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document.write( "\"x%5E2%2B8x%2B16%2By%5E2-2y%2B1=-15%2B16%2B1\"\r\n" );
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document.write( "Factor the first three terms on the left as a perfect square:\r\n" );
document.write( "Factor the last three terms on the left as a perfect square:\r\n" );
document.write( "Combine the numbers on the right side:\r\n" );
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document.write( "\"%28x%2B4%29%5E2%2B%28y-1%29%5E2=2\"\r\n" );
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document.write( "Compare that to the standard equation of a circle, which is:\r\n" );
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document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\"\r\n" );
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document.write( "where the center is \"%22%28h%2Ck%29%22\"\r\n" );
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document.write( "So \"h=-4\", \"k=1\", \"r%5E2=2\"\r\n" );
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document.write( "Therefore the center is the point \"%22%28h%2Ck%29%22=%22%28-4%2C1%29%22\"\r\n" );
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document.write( "And since \r\n" );
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document.write( "\"r%5E2=2\", we take the square root of both sides, \r\n" );
document.write( "and get\r\n" );
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document.write( "\"r=sqrt%282%29\"\r\n" );
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document.write( "So the radius of the circle is \"sqrt%282%29\".\r\n" );
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document.write( "Edwin
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