document.write( "Question 244657: the length of a rectangle is four more than one-half the width of the rectangle. the perimeter of the rectangle is 50. The area of the rectangle is _______square units. \r
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document.write( "the length of the diagonal of the rectangle, to the nearest tenth is ________units. \n" );
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Algebra.Com's Answer #178874 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! the length of a rectangle is four more than one-half the width of the rectangle. \n" ); document.write( "------------------------------ \n" ); document.write( "Let width be \"x\". \n" ); document.write( "Then the length is \"(1/2)x+4\" \n" ); document.write( "------------------------------\r \n" ); document.write( "\n" ); document.write( "the perimeter of the rectangle is 50. \n" ); document.write( "P + 2(length + width) \n" ); document.write( "50 = 2[(1/2)x+4 + x] \n" ); document.write( "25 = (3/2)x + 4 \n" ); document.write( "(3/2)x = 21 \n" ); document.write( "x = 14 (width) \n" ); document.write( "(1/2)x+4 = 7+4 = 11 (length) \n" ); document.write( "---------------------------------\r \n" ); document.write( "\n" ); document.write( "The area of the rectangle is 14*11 = 154 square units. \n" ); document.write( "the length of the diagonal of the rectangle, \n" ); document.write( "to the nearest tenth is sqrt(21^2+11^2) = sqrt(562) = 23.71 units. \n" ); document.write( "=================================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |