document.write( "Question 244644: how do you condense the following logarithms? I'm confused and need help.\r
\n" ); document.write( "\n" ); document.write( "3 log3X + 4 log3Y-4log3Z\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "2[3 ln x-ln(x+1)-ln(x-1)]
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Algebra.Com's Answer #178870 by JimboP1977(311)\"\" \"About 
You can put this solution on YOUR website!
Log Rules that you should learn:\r
\n" ); document.write( "\n" ); document.write( "1) \"logb%28mn%29+=+logb%28m%29+%2B+logb%28n%29\"\r
\n" ); document.write( "\n" ); document.write( "2) \"logb%28m%2Fn%29+=+logb%28m%29+%96+logb%28n%29\"\r
\n" ); document.write( "\n" ); document.write( "3) \"logb%28m%5En%29+=+n+%B7+logb%28m%29\"\r
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\n" ); document.write( "\n" ); document.write( "Assuming log3 means log(base 3):\r
\n" ); document.write( "\n" ); document.write( "\"3+log3X+%2B+4+log3Y-4log3Z+\"
\n" ); document.write( "\"log3x%5E3%2Blog3Y%5E4-log3Z%5E4\" Using rule 3
\n" ); document.write( "\"log3+%28x%5E3%2Ay%5E4%29%2Fz%5E4\" Using rule 1 and 2\r
\n" ); document.write( "\n" ); document.write( "\"2%283+ln+x-ln%28x%2B1%29-ln%28x-1%29%29\"
\n" ); document.write( "\"2%28+ln+x%5E3-ln%28x%2B1%29-ln%28x-1%29%29\" Using rule 3
\n" ); document.write( "\"2%28+ln+%28%28x%5E3%2F%28x%2B1%29%29%2F%28x-1%29%29%29\" Using rule 2
\n" ); document.write( "\"ln+%28x%5E3%2F%28%28x%2B1%29%2A%28x-1%29%29%29%5E2\" Using rule 3
\n" ); document.write( "\"ln+%28x%5E6%2F%28%28x%2B1%29%5E2%2A%28x-1%29%5E2%29%29\"
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