document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=244500>Question 244500</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man is 30 years old and his son is 4 years old,after how many years will the man be twice as old as his son? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178831 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In t years the man will be 30 + t years old<BR>\n" );
document.write( "in t years the son will be 4+t years old.<BR>\n" );
document.write( "in t years the man (30+t)   will be twice 2* as old as the son (4+t) \r<BR>\n" );
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document.write( "30+t=2(4+t)<BR>\n" );
document.write( "30+t=8+2t<BR>\n" );
document.write( "subtract 8 from both sides <BR>\n" );
document.write( "22+t=2t=t+t<BR>\n" );
document.write( "and subtract t from both sides<BR>\n" );
document.write( "22=t<BR>\n" );
document.write( "In 22 years the man will be 52 and the son will be 26.<BR>\n" );
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