document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=244500>Question 244500</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man is 30 years old and his son is 4 years old,after how many years will the man be twice as old as his son? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178824 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let M = the man's present age and S = the son's present age, so...<BR>\n" );
document.write( "M = 30 and S = 4.<BR>\n" );
document.write( "Let x = the number of years in which the man's age will be twice the son's age.<BR>\n" );
document.write( "M+x = 2(S+x) Substitute M = 30 and S = 4.<BR>\n" );
document.write( "30+x = 2(4+x) Simplify.<BR>\n" );
document.write( "30+x = 8+2x Subtract x from both sides.<BR>\n" );
document.write( "30 = 8+x Subtract 8 from both sides.<BR>\n" );
document.write( "22 = x<BR>\n" );
document.write( "The man will be twice the son's age in 22 years.<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "In 22 years, the man will be 30+22 = 52 years old.<BR>\n" );
document.write( "In 22 years, the son will be 4+22 = 26 years old.<BR>\n" );
document.write( "52 = 2(26)<BR>\n" );
document.write( " </SPAN>\n" );
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