document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=244488>Question 244488</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measure of two complementary angles if the difference in teh measure is 16? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178813 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178813\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x & x+16 are the 2 angles.<BR>\n" );
document.write( "x+x+16=90<BR>\n" );
document.write( "2x=90-16<BR>\n" );
document.write( "2x=74<BR>\n" );
document.write( "x=37 degrees ans.<BR>\n" );
document.write( "37+16=53 degrees ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "37+53=90<BR>\n" );
document.write( "90=90 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );