document.write( "Question 31158This question is from textbook college algebra
\n" ); document.write( ": 25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3] \n" ); document.write( "
Algebra.Com's Answer #17879 by gymnast2598(2)\"\" \"About 
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25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3]
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\n" ); document.write( " distribute the -3 and 5
\n" ); document.write( "25-2+5y-3y-6=-6y+15-5y-5-3y+3
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\n" ); document.write( " combine all variables
\n" ); document.write( "17+2y=8-14y
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\n" ); document.write( "subtract seventeen from here ↑
\n" ); document.write( "2y=-9-14y
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\n" ); document.write( "add 14y to here↑
\n" ); document.write( "16y = -9
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