document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=244341>Question 244341</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by the substitution method.  I have part of this I will add it here and hopefully someone can help me with the last part.  \r<BR>\n" );
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document.write( "Solve by the substitution method.\r<BR>\n" );
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document.write( "8x+2y=-46<BR>\n" );
document.write( "-6x+y=47\r<BR>\n" );
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document.write( "Ok, so you start with the second equation to make it more simple. \r<BR>\n" );
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document.write( "1(-6x+47)\r<BR>\n" );
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document.write( "y=-6x+47\r<BR>\n" );
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document.write( "Substitute that for y in the first equation.\r<BR>\n" );
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document.write( "8x+2(-6x+47)=-46<BR>\n" );
document.write( "8x-12+94=-46\r<BR>\n" );
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document.write( "Collect like terms. \r<BR>\n" );
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document.write( "-4x+94-94=-46+94\r<BR>\n" );
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document.write( "-4x=48\r<BR>\n" );
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document.write( "x=-12\r<BR>\n" );
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document.write( "Is this correct so far?  \r<BR>\n" );
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document.write( "So next you would take -12 and substitute it into the second equation. \r<BR>\n" );
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document.write( "-6(-12)+47\r<BR>\n" );
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document.write( "72+47\r<BR>\n" );
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document.write( "y=119\r<BR>\n" );
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document.write( "So my ordered pair would be \r<BR>\n" );
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document.write( "(-12,119)\r<BR>\n" );
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document.write( "except I know this is wrong, I am just wondering exactly what I did wrong here.  Thanks in advance.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178758 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178758\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -6x+y=47 ___ adding 6x ___ y = 6x + 47\r<BR>\n" );
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document.write( "substituting ___ 8x + 2(6x + 47) = -46 ___ 20x + 94 = -46 ___ 20x = -140 ___ x = -7\r<BR>\n" );
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document.write( "substituting ___ -6(-7) + y = 47 ___ 42 + y = 47 ___ y = 5 </SPAN>\n" );
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