document.write( "Question 31173This question is from textbook Into Algebra
\n" ); document.write( ": A car travels 90 miles in the same time that car travelins 10 miles per hour slower travels 60 miles. Find the speed of each car. \n" ); document.write( "
Algebra.Com's Answer #17875 by mbarugel(146)\"\" \"About 
You can put this solution on YOUR website!
Hello!
\n" ); document.write( "Let's call X to the speed of the fast car. The time needed for a car going at X miles per hour (mph) to travel 90 miles is:\r
\n" ); document.write( "\n" ); document.write( "\"90%2FX\"
\n" ); document.write( "[for example, if it were going at 45 mph, it would need 2 hours to travel 90 miles]\r
\n" ); document.write( "\n" ); document.write( "The other car travles 10 mph slower; that is, at \"X-10\" mph. The time it takes this car to travel 60 miles would then be:\r
\n" ); document.write( "\n" ); document.write( "\"60%2F%28X-10%29\"\r
\n" ); document.write( "\n" ); document.write( "But we also know that these times are equal. So we have the equation:\r
\n" ); document.write( "\n" ); document.write( "\"90%2FX+=+60%2F%28X-10%29\"
\n" ); document.write( "Cross-multiplying:
\n" ); document.write( "\"90X+-+900+=+60X\"
\n" ); document.write( "\"30X+=+900\"
\n" ); document.write( "\"X+=+30\"\r
\n" ); document.write( "\n" ); document.write( "The fast car travels at 30 mph; the other one, at 20 mph.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "I hope this helps!\r
\n" ); document.write( "\n" ); document.write( "Get more answers at Online Math Answers.com!
\n" ); document.write( "
\n" ); document.write( "
\n" );