document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=244238>Question 244238</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would I do y=x-6 on a graph as a linear line? Because I don't know what the rise over run is but I know the Y intercept... So how would I graph it or figure out what the x is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178729 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178729\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=x-6<BR>\n" );
document.write( "The rise over run is the slope (m)<BR>\n" );
document.write( "Y=mX+b <BR>\n" );
document.write( "In this equation m=1.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+8%2C+-10%2C+10%2C+x+-6%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-6%2C+8%2C+-10%2C+10%2C+x+-6%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 300x200 pixels, x from -6 to 8, y from -10 to 10, x -6).  </SPAN>\n" );
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