document.write( "Question 244162: How do you work the problem 2(x+3)^2-4=24 \n" ); document.write( "

Algebra.Com's Answer #178705 by checkley77(12844) $\"\"$ $\"About$

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2(x+3)^2-4=24
\n" ); document.write( "2(X^2+6X+9)-4-24=0
\n" ); document.write( "2X^2+12X+18-28=0
\n" ); document.write( "2X^2+12X-10=0
\n" ); document.write( "2(X^2+6X-5)=0
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "X=(-6+-SQRT[6^2-4*1*-5])/2*1
\n" ); document.write( "X=(-6+-SQRT[36+20])/2
\n" ); document.write( "X=(-6+-SQRT56)/2
\n" ); document.write( "X=(-6+-7.48)/2
\n" ); document.write( "X=(-6+7.48)/2
\n" ); document.write( "X=1.48/2
\n" ); document.write( "X=.74 ANS.
\n" ); document.write( "X=(-6-7.48)/2
\n" ); document.write( "X=-13/48/2
\n" ); document.write( "X=-6.74 ANS. \n" ); document.write( "

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