document.write( "Question 31172: Hello! I have tried this problem over and over again but I can't seem to get it. Please help.\r
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document.write( "A regular hexagon has sides four feet long. Find the area of the triangle formed by connecting alternate vertices.\r
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document.write( "I know your supposed to show your previous work, but honestly, I don't even know where to start! I really need your help. Thank you so very much. \n" );
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Algebra.Com's Answer #17867 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! not sure exactly which is the triangle you are asking for. Label the vertices as A, B, C, D, E, F then draw a line between A and C...you mean the triangle ABC?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If so, we have Area=(1/2)absinC --> the notation here is nothing to do with the labelling of the vertices.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a=AB \n" ); document.write( "b=BC\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and a=b=4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "angle C is angle ABC. This is an interior angle of a hexagon.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To find the interior angle of an hexagon: \n" ); document.write( "A hexagon is 6sided. This can be divided into 4 triangles. \n" ); document.write( "4 triangles have 4*180 angles between them --> 720degrees.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So each interior angle = 720/6 --> 120degrees\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so area= (1/2)*4*4*sin120 \n" ); document.write( "8sin120 \n" ); document.write( "8*sqrt(3)/2 \n" ); document.write( "4sqrt(3) is the area of triangle ABC.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |