document.write( "Question 244059: I hope you can help
\n" ); document.write( "A car travels 180 miles. A second car, traveling 15 m/h faster than the first car, makes the same trip in 1 hour less time. Find the speed of each car.
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Algebra.Com's Answer #178658 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let represent the distance traveled by the first car.\r
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\n" ); document.write( "\n" ); document.write( "Let represent the speed of the first car\r
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\n" ); document.write( "\n" ); document.write( "Let represent the travel time of the first car\r
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\n" ); document.write( "\n" ); document.write( "Then represents the distance traveled by the second car also.\r
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\n" ); document.write( "\n" ); document.write( "And represents the speed of the second car\r
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\n" ); document.write( "\n" ); document.write( "And represents the travel time for the second car.\r
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\n" ); document.write( "\n" ); document.write( "Since we know that distance is equal to rate times time, we can say with respect to the trip taken by the first car:\r
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\n" ); document.write( "\n" ); document.write( "And with respect to the trip taken by the second car:\r
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\n" ); document.write( "\n" ); document.write( "Multiply the second equation by \r
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\n" ); document.write( "\n" ); document.write( "Add 1 to both sides:\r
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\n" ); document.write( "\n" ); document.write( "Multiply the first equation by \r
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\n" ); document.write( "\n" ); document.write( "Set the two expressions that are equal to Let equal to each other:\r
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\n" ); document.write( "\n" ); document.write( "Simplify and then solve the resulting quadratic for . Exclude the negative root. The positive root will be the speed of the first car. Add 15 to find the speed of the second car.\r
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