document.write( "Question 243990: A person runs 3 miles and walks 2 miles. He runs twice as fast as he walks and finishes in exactly one hour. How fast does he walk.
\n" ); document.write( "I am completely lost and not sure why. The book gives simply the answer, 3.5 mph. I have:
\n" ); document.write( "r = d/t \n" ); document.write( "

Algebra.Com's Answer #178646 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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A person runs 3 miles and walks 2 miles.
\n" ); document.write( " He runs twice as fast as he walks and finishes in exactly one hour.
\n" ); document.write( " How fast does he walk.
\n" ); document.write( ":
\n" ); document.write( "let r = walking speed
\n" ); document.write( "then
\n" ); document.write( "2r = running speed
\n" ); document.write( ":
\n" ); document.write( "Write a time equation time = dist/rate
\n" ); document.write( "Walk time + run time = 1 hr
\n" ); document.write( " $\"2%2Fr\"$ + $\"3%2F%282r%29\"$ = 1
\n" ); document.write( "Multiply by 2r
\n" ); document.write( "2(2) + 3 = 2r
\n" ); document.write( "4 + 3 = 2r
\n" ); document.write( "r = $\"7%2F2\"$
\n" ); document.write( "r = 3.5 mph walking rate
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution
\n" ); document.write( "2/3.5 + 3/7 = 1 \n" ); document.write( "

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