document.write( "Question 244029: 6x^2+13x-5= \n" ); document.write( "

Algebra.Com's Answer #178640 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
I'm assuming that you want to factor.\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression $\"6x%5E2%2B13x-5\"$ , we can see that the first coefficient is $\"6\"$ , the second coefficient is $\"13\"$ , and the last term is $\"-5\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient $\"6\"$ by the last term $\"-5\"$ to get $\"%286%29%28-5%29=-30\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to $\"-30\"$ (the previous product) and add to the second coefficient $\"13\"$ ?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of $\"-30\"$ (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of $\"-30\"$ :\r
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\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-5,-6,-10,-15,-30\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to $\"-30\"$ .\r
\n" ); document.write( "\n" ); document.write( "1*(-30)
\n" ); document.write( "2*(-15)
\n" ); document.write( "3*(-10)
\n" ); document.write( "5*(-6)
\n" ); document.write( "(-1)*(30)
\n" ); document.write( "(-2)*(15)
\n" ); document.write( "(-3)*(10)
\n" ); document.write( "(-5)*(6)\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient $\"13\"$ :\r
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First Number	Second Number	Sum
1	-30	1+(-30)=-29
2	-15	2+(-15)=-13
3	-10	3+(-10)=-7
5	-6	5+(-6)=-1
-1	30	-1+30=29
-2	15	-2+15=13
-3	10	-3+10=7
-5	6	-5+6=1

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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers $\"-2\"$ and $\"15\"$ add to $\"13\"$ (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers $\"-2\"$ and $\"15\"$ both multiply to $\"-30\"$ and add to $\"13\"$ \r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term $\"13x\"$ with $\"-2x%2B15x\"$ . Remember, $\"-2\"$ and $\"15\"$ add to $\"13\"$ . So this shows us that $\"-2x%2B15x=13x\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"6x%5E2%2Bhighlight%28-2x%2B15x%29-5\"$ Replace the second term $\"13x\"$ with $\"-2x%2B15x\"$ .\r
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\n" ); document.write( "\n" ); document.write( " $\"%286x%5E2-2x%29%2B%2815x-5%29\"$ Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( " $\"2x%283x-1%29%2B%2815x-5%29\"$ Factor out the GCF $\"2x\"$ from the first group.\r
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\n" ); document.write( "\n" ); document.write( " $\"2x%283x-1%29%2B5%283x-1%29\"$ Factor out $\"5\"$ from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( " $\"%282x%2B5%29%283x-1%29\"$ Combine like terms. Or factor out the common term $\"3x-1\"$ \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So $\"6x%5E2%2B13x-5\"$ factors to $\"%282x%2B5%29%283x-1%29\"$ .\r
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\n" ); document.write( "\n" ); document.write( "In other words, $\"6x%5E2%2B13x-5=%282x%2B5%29%283x-1%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by FOILing $\"%282x%2B5%29%283x-1%29\"$ to get $\"6x%5E2%2B13x-5\"$ or by graphing the original expression and the answer (the two graphs should be identical).
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