document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=243985>Question 243985</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In any triangle, the sum of the measures of the angles is 180° . In &#916;ABC, &#8738; A is three<BR>\n" );
document.write( "times as large as &#8738; B and also 16° larger than &#8738; C. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178617 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178617\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a=first angle<BR>\n" );
document.write( "b=second angle<BR>\n" );
document.write( "c=third angle<BR>\n" );
document.write( "a=3b<BR>\n" );
document.write( "a=16+c<BR>\n" );
document.write( "solve for a<BR>\n" );
document.write( "b=a/3<BR>\n" );
document.write( "c=a-16<BR>\n" );
document.write( "a+b+c=180<BR>\n" );
document.write( "substitute<BR>\n" );
document.write( "a+a/3+a-16=180<BR>\n" );
document.write( "combine and reduce<BR>\n" );
document.write( "2a +a/3=196<BR>\n" );
document.write( "divide by 2<BR>\n" );
document.write( "a+a/6=98<BR>\n" );
document.write( "multiply by 6<BR>\n" );
document.write( "6a+a=6*98<BR>\n" );
document.write( "7a=6*98<BR>\n" );
document.write( "7a=588<BR>\n" );
document.write( "a=588/7<BR>\n" );
document.write( "a=84<BR>\n" );
document.write( "b=a/3=28<BR>\n" );
document.write( "c=a-16=84-16=68<BR>\n" );
document.write( "check\r<BR>\n" );
document.write( "\n" );
document.write( "84+28+68=180<BR>\n" );
document.write( "180=180 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );