document.write( "Question 243385: find the measure of an angle such that the difference between the measures of its supplement and three times its complement is 10 degrees \n" ); document.write( "
Algebra.Com's Answer #178566 by ankor@dixie-net.com(22740)\"\" \"About 
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find the measure of an angle such that the difference between the measures of its supplement and three times its complement is 10 degrees
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\n" ); document.write( "Let = the angle
\n" ); document.write( "then
\n" ); document.write( "(180-x) = it's supplement
\n" ); document.write( "and
\n" ); document.write( "(90-x) = it's complement
\n" ); document.write( ":
\n" ); document.write( "The equation for:
\n" ); document.write( "\"the difference between the measures of its supplement and three times its complement is 10 degrees\"
\n" ); document.write( "(180-x) - 3(90-x) = 10
\n" ); document.write( ":
\n" ); document.write( "180 - x - 270 + 3x = 10
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\n" ); document.write( "Combine like terms:
\n" ); document.write( "-x + 3x + 180 - 270 = 10
\n" ); document.write( ":
\n" ); document.write( "2x - 90 = 10
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\n" ); document.write( "2x = 10 + 90
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\n" ); document.write( "2x = 100
\n" ); document.write( "x = \"100%2F2\"
\n" ); document.write( "x = 50 degrees
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\n" ); document.write( "Is this true?
\n" ); document.write( "(180-50) - 3(90-50) = 10
\n" ); document.write( "130 - 3(40) = 10; confirms our solution \n" ); document.write( "
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