document.write( "Question 243737: The area of a rectangle is 80 square feet. The length is 2 feet longer than the width. Find the measure of each. \n" ); document.write( "
Algebra.Com's Answer #178542 by oberobic(2304)\"\" \"About 
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We know the area of a rectangle is width times the length.
\n" ); document.write( "\"A+=+W+%2A+L\"
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\n" ); document.write( "We are told A = 80
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\n" ); document.write( "We also are told L is 2 feet longer than the width.
\n" ); document.write( "\"L+=+W+%2B+2\"
\n" ); document.write( "or
\n" ); document.write( "\"W+=+L+-+2\"
\n" ); document.write( "You pick.
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\n" ); document.write( "Substituting what we know:
\n" ); document.write( "\"A+=+W+%2A+L\"
\n" ); document.write( "\"80+=+%28L-2%29+%2A+L\"
\n" ); document.write( "Multiplying through the right-hand:
\n" ); document.write( "\"80+=+L%5E2+-+2L\"
\n" ); document.write( "Equal things are equal, so we can rewrite:
\n" ); document.write( "\"L%5E2+-+2L+=+80\"
\n" ); document.write( "Subracting 80 from both sides
\n" ); document.write( "\"L%5E2+-+2L+-+80+=+0\"
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\n" ); document.write( "We now consider whether it can be factored. The factors of 80 are 2*40, 4*20, 5*18, 8*10...
\n" ); document.write( "We have to have different signs to get them to multiply to -80.
\n" ); document.write( "And we need them to be 2 apart to have the solve the L term. 8 & 10 is the way to go.
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\n" ); document.write( "\"%28L-10%29%28L%2B8%29+=+0\"
\n" ); document.write( ".
\n" ); document.write( "So we have two candidate solutions: L=10 and L=-8.
\n" ); document.write( "Since we are talking about the area of a rectangle, a length of -8 is not reasonable. So we'll test 10.
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\n" ); document.write( "Looking back at the equations we established:
\n" ); document.write( "\"W+=+L+-+2+=+10+-+2+=+8\"
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\n" ); document.write( "So we propose the L=10 and W=8.
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\n" ); document.write( "Checking the Area, we test:
\n" ); document.write( "\"A+=+L+%2A+W+=+10+%2A+8+=+80\"
\n" ); document.write( ".
\n" ); document.write( "That checks. So we're done.
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