document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=243719>Question 243719</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve using the substitution method.\r<BR>\n" );
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document.write( "y = 2x - 5<BR>\n" );
document.write( "3x + y = 15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178523 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178523\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let's first set both equations up so they have the variables on one side.<BR>\n" );
document.write( "In the first equation subtract 2x from both sides so it will look like: <BR>\n" );
document.write( "-2x + y = - 5<BR>\n" );
document.write( "3x + y = 15<BR>\n" );
document.write( "OK, Now let's multiply the first equation by -1 to give us:<BR>\n" );
document.write( "+2x - y = + 5<BR>\n" );
document.write( "3x + y = 15<BR>\n" );
document.write( "With this we can add both equations to be:<BR>\n" );
document.write( "5x=20  Divide both sides by 5:<BR>\n" );
document.write( "x=4<BR>\n" );
document.write( "Now in the original equation replace x with 4:<BR>\n" );
document.write( "y = 2(4) - 5  Do the calculation gives us: <BR>\n" );
document.write( "y=3<BR>\n" );
document.write( "We now have x=4 and y=3. Plug these into both equations to see if they work. <BR>\n" );
document.write( "RJ Toftness<BR>\n" );
document.write( "www.math-unlock.com<BR>\n" );
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