document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=243639>Question 243639</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 110cm. one side is twice the second side. the third side is 30cm more than the second side. find the length of each side </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178479 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178479\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle = a + b + c.<BR>\n" );
document.write( "where<BR>\n" );
document.write( "a = first side<BR>\n" );
document.write( "b = second side<BR>\n" );
document.write( "c = third side<BR>\n" );
document.write( ".<BR>\n" );
document.write( "We are told P = 110.<BR>\n" );
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document.write( "To solve word problems, it usually is best to define these variables in terms of one another, which the problem tells you how to do so.  For example,<BR>\n" );
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document.write( "a = a<BR>\n" );
document.write( "b = 2a<BR>\n" );
document.write( "c = b+30 = 2a+30<BR>\n" );
document.write( ".<BR>\n" );
document.write( "110 = a + b + c<BR>\n" );
document.write( "Substituting for 'b' and 'c' defined in terms of 'a'.<BR>\n" );
document.write( "110 = a + 2a + 2a+30<BR>\n" );
document.write( "Collecting terms<BR>\n" );
document.write( "110 = 5a + 30<BR>\n" );
document.write( "Subtract 30 from both sides<BR>\n" );
document.write( "80 = 5a<BR>\n" );
document.write( "Equals are equal, so<BR>\n" );
document.write( "5a = 80<BR>\n" );
document.write( "Divide both sides by 5<BR>\n" );
document.write( "a = 16<BR>\n" );
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document.write( "Substituting back into the formulas we set up above.\r<BR>\n" );
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document.write( "b = 2a = 2(16) = 32<BR>\n" );
document.write( "c = b + 30 = 32 + 30 = 62<BR>\n" );
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document.write( "Checking our work:<BR>\n" );
document.write( "a + b + c = 16 + 32 + 62 = 110<BR>\n" );
document.write( "Done. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );