document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=243561>Question 243561</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 800 feet, and length of it is 50 feet less than half the width. What are it's dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178453 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=W/2-50<BR>\n" );
document.write( "P=2L+2W<BR>\n" );
document.write( "800=2(W/2-50)+2W<BR>\n" );
document.write( "800=W-100+2W<BR>\n" );
document.write( "800+100=3W<BR>\n" );
document.write( "900=3W<BR>\n" );
document.write( "900/3=W<BR>\n" );
document.write( "3OO=W ANS. FOR THE WIDTH.<BR>\n" );
document.write( "L=300/2-50<BR>\n" );
document.write( "L=150-50<BR>\n" );
document.write( "L=100 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "800=2*100+2*300<BR>\n" );
document.write( "800=200+600<BR>\n" );
document.write( "800=800 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );