document.write( "Question 243590: I am struggling on a few word problems on my homework, please help me, it is due tomorrow!\r
\n" ); document.write( "\n" ); document.write( "You have 280 feet of fencing. Do you have enough to fence a rectangular region with an area of 4850 sq. ft. ?\r
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\n" ); document.write( "\n" ); document.write( "In 1987, your uncle opened a neighborhood grocery store. for 1987-2007 his annual sales, S(in millions of dollars) could be modeled by S= -0.035t^2 + 0.8t + 0.5 where t=0 represents 1987. During which years of operation were his annual sales 3 million dollars? \n" ); document.write( "
Algebra.Com's Answer #178448 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
(1) Since I don't know the dimensions of the rectangle, I will assume it is a square. Given the area = 4850, then the sides are the square root of 4850, which = 69.64. Since the perimeter of a square is simply 4s, s = length of a side, then YES your 280 ft of fencing can do the job.
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\n" ); document.write( "(2) This one requires you to set up the given equation and then substitute the values of t, where
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document.write( "year   t\r\n" );
document.write( "1987   0\r\n" );
document.write( "1988   1\r\n" );
document.write( "1989   2\r\n" );
document.write( "1990   3\r\n" );
document.write( "etc.\r\n" );
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\n" ); document.write( "The equation is
\n" ); document.write( "\"Sales+=+-0.035t%5E2+%2B+0.8t+%2B+0.5\"
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\n" ); document.write( "Using Excel, I created the following table for the years 1987-2007. Notice that the sales go up for a while and then start back down.
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document.write( "yr	t	Sales\r\n" );
document.write( "1987	0	0.500\r\n" );
document.write( "1988	1	1.265\r\n" );
document.write( "1989	2	1.960\r\n" );
document.write( "1990	3	2.585\r\n" );
document.write( "1991	4	3.140\r\n" );
document.write( "1992	5	3.625\r\n" );
document.write( "1993	6	4.040\r\n" );
document.write( "1994	7	4.385\r\n" );
document.write( "1995	8	4.660\r\n" );
document.write( "1996	9	4.865\r\n" );
document.write( "1997	10	5.000\r\n" );
document.write( "1998	11	5.065\r\n" );
document.write( "1999	12	5.060\r\n" );
document.write( "2000	13	4.985\r\n" );
document.write( "2001	14	4.840\r\n" );
document.write( "2002	15	4.625\r\n" );
document.write( "2003	16	4.340\r\n" );
document.write( "2004	17	3.985\r\n" );
document.write( "2005	18	3.560\r\n" );
document.write( "2006	19	3.065\r\n" );
document.write( "2007	20	2.500\r\n" );
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