document.write( "Question 243576: a motorboat took 2 hours to make a downstream trip with a 5mph current. The return trip against the same current took 4 hours. Find the speed of the boat in still water. \n" ); document.write( "
Algebra.Com's Answer #178444 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "D=(X+5)*2
\n" ); document.write( "D=(X-5)*4
\n" ); document.write( "(X+5)*2=(X-5)*4
\n" ); document.write( "2X+10=4X-20
\n" ); document.write( "2X-4X=-20-10
\n" ); document.write( "-2X=-30
\n" ); document.write( "X=-30/-2
\n" ); document.write( "X=15 MPH IS THE SPEED OF THE BOAT IN STILL WATER.
\n" ); document.write( "PROOF:
\n" ); document.write( "(15+5)*2=(15-5)*4
\n" ); document.write( "20*2=10*4
\n" ); document.write( "40=40
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