document.write( "Question 243576: a motorboat took 2 hours to make a downstream trip with a 5mph current. The return trip against the same current took 4 hours. Find the speed of the boat in still water. \n" ); document.write( "
Algebra.Com's Answer #178444 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "D=(X+5)*2 \n" ); document.write( "D=(X-5)*4 \n" ); document.write( "(X+5)*2=(X-5)*4 \n" ); document.write( "2X+10=4X-20 \n" ); document.write( "2X-4X=-20-10 \n" ); document.write( "-2X=-30 \n" ); document.write( "X=-30/-2 \n" ); document.write( "X=15 MPH IS THE SPEED OF THE BOAT IN STILL WATER. \n" ); document.write( "PROOF: \n" ); document.write( "(15+5)*2=(15-5)*4 \n" ); document.write( "20*2=10*4 \n" ); document.write( "40=40 \n" ); document.write( " \n" ); document.write( " |