document.write( "Question 243596: Please help me solve this equation: ((2x^2-8x-42)/(6x^2))/((x^2-9)/(x^2-3x)) \n" ); document.write( "
Algebra.Com's Answer #178439 by jim_thompson5910(35256)\"\" \"About 
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\"%28%282x%5E2-8x-42%29%2F%286x%5E2%29%29%2F%28%28x%5E2-9%29%2F%28x%5E2-3x%29%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28%282x%5E2-8x-42%29%2F%286x%5E2%29%29%2A%28%28x%5E2-3x%29%2F%28x%5E2-9%29%29\" Multiply the first fraction by the reciprocal of the second fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"%28%282%2A%28x%2B3%29%2A%28x-7%29%29%2F%286x%5E2%29%29%28%28x%5E2-3x%29%2F%28x%5E2-9%29%29\" Factor \"2x%5E2-8x-42\" to get \"2%2A%28x%2B3%29%2A%28x-7%29\".\r
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\n" ); document.write( "\n" ); document.write( " Factor \"6x%5E2\" to get \"2%2A3%2Ax%2Ax\".\r
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\n" ); document.write( "\n" ); document.write( " Factor \"x%5E2-3x\" to get \"x%2A%28x-3%29\".\r
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\n" ); document.write( "\n" ); document.write( " Factor \"x%5E2-9\" to get \"%28x-3%29%2A%28x%2B3%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2Ax%2A%28x%2B3%29%2A%28x-7%29%28x-3%29%29%2F%282%2A3%2Ax%2Ax%28x-3%29%2A%28x%2B3%29%29\" Combine the fractions. \r
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\n" ); document.write( "\n" ); document.write( " Highlight the common terms. \r
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\n" ); document.write( "\n" ); document.write( " Cancel out the common terms. \r
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\n" ); document.write( "\n" ); document.write( "\"%28x-7%29%2F%283x%29\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So \"%28%282x%5E2-8x-42%29%2F%286x%5E2%29%29%2F%28%28x%5E2-9%29%2F%28x%5E2-3x%29%29\" simplifies to \"%28x-7%29%2F%283x%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \r
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