document.write( "Question 31068: 3 men were charged $10 each for the sales item. Since the items were not new, the seller decided to gave them a deal. He gave his son $5 and told him to give each man a $1 back. His son kept $2 for himself and gave the men $1 each. What happened to the remaining dollar? \r
\n" ); document.write( "\n" ); document.write( "3 X 10 = 30 total cost
\n" ); document.write( "30 - 5 = 25 refund
\n" ); document.write( "25 - 3 = 22 men's refund
\n" ); document.write( "22 - 2 = son kept
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Algebra.Com's Answer #17842 by Earlsdon(6294)\"\" \"About 
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Let's see if I've got this right.
\n" ); document.write( "The three men paid $10.00 each ($30.00) and were refunded $1.00 each ($3.00), so in effect, they paid $27.00 (3 X $9.00) as a group, right? So where's the $27.00?
\n" ); document.write( "Well, the seller has $25.00 and his son has $2.00.
\n" ); document.write( "So, $25.00 + $2.00 = $27.00 What missing dollar?\r
\n" ); document.write( "\n" ); document.write( "Another way to look at it.
\n" ); document.write( "The three men each paid $10.00 for a total of $30.00
\n" ); document.write( "Where's the $30.00?
\n" ); document.write( "The seller has $25.00.
\n" ); document.write( "The son has $2.00
\n" ); document.write( "The three men have $1.00 each or $3.00 altogether.
\n" ); document.write( "So, $25.00 + $2.00 + $3.00 = $30.00
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