document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4000>Question 4000</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value(s) of w so that the points (0,3) and (6,w) are 10 units apart. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1784 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1784\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can use the distance formula to solve this problem.\r<BR>\n" );
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document.write( "d = sqrt[(x2 - x1)^2 + (y2 - y1)^2], where:   x1 = 0, x2 = 6, y1 = 3, y2 = w, and d = 10\r<BR>\n" );
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document.write( "10 = sqrt[(6-0)^2 + (w-3)^2]\r<BR>\n" );
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document.write( "10 = sqrt[36 + (w-3)^2]   Square both sides.\r<BR>\n" );
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document.write( "100 = 36 + (w^2 - 6w + 9) Simplify.\r<BR>\n" );
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document.write( "w^2 - 6w + 45 = 100   Subtract 100 from both sides.\r<BR>\n" );
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document.write( "w^2 - 6w - 55 = 0    Solve the quadratic equation by factoring.\r<BR>\n" );
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document.write( "(w - 11)(w + 5) = 0  Apply the zero products principle.\r<BR>\n" );
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document.write( "w - 11 = 0,  w = 11<BR>\n" );
document.write( "w + 5 = 0,  w = -5\r<BR>\n" );
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document.write( "The values of w are:  11 and -5 </SPAN>\n" );
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