document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31132>Question 31132</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0131449729/algebrahomeworkh>Intro Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> a boat can travel a 9 minles upstream in the same time amount of time it takes to travel 11 miles downstream. if the current of the river is 3 miles per hour, complete the chart below and use it to find the speen r of the boat in still water\r<BR>\n" );
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document.write( "          Dis= rate * time    <BR>\n" );
document.write( "upstream   9    r-3<BR>\n" );
document.write( "downstream 11   r+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17839 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17839\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEE BELOW<BR>\n" );
document.write( "a boat can travel a 9 minles upstream in the same time amount of time it takes to travel 11 miles downstream. if the current of the river is 3 miles per hour, complete the chart below and use it to find the speen r of the boat in still water\r<BR>\n" );
document.write( "\n" );
document.write( "Dis= rate * time<BR>\n" );
document.write( "upstream 9 r-3...NO IT IS 9=(R-3)*T.....................I<BR>\n" );
document.write( "downstream 11 r+3..NO IT IS ...11=(R+3)*T..................II<BR>\n" );
document.write( "EQN.II/EQN.I GIVES<BR>\n" );
document.write( "(R+3)T/(R-3)T = 11/9<BR>\n" );
document.write( "(R+3)/(R-3)=11/9<BR>\n" );
document.write( "(R+3+R-3)/(R+3-R+3)=(11+9)/(11-9)=20/2=10<BR>\n" );
document.write( "2R/6=10<BR>\n" );
document.write( "R/3=10<BR>\n" );
document.write( "R=10*=30 </SPAN>\n" );
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