document.write( "Question 243494: how much pure acid should be mixed with 9 gallons of a 50% acid solution in order to get an 80% acid solution \n" ); document.write( "
Algebra.Com's Answer #178389 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! Always start by sorting out what you know and assigning variables. We know we have 9 gallons of 50% acid solution. Multiplying 9 by .5 = 4.5 gallons of pure acid in the solution. \n" ); document.write( ". \n" ); document.write( "We need to know how much more pure acid we need to add to get an 80% acid solution. \n" ); document.write( ". \n" ); document.write( "Set the unknown to x. \n" ); document.write( ". \n" ); document.write( "Since we are adding x gallons of pure acid, the final solution will be 9+x gallons at 80% acid. We can state this algebraically as: .8(9+x) \n" ); document.write( ". \n" ); document.write( "It will consist of 9 gallows of .5 acid solution + x gallons of 100% acid. We can show this as \n" ); document.write( ".5(9) + 1(x) \n" ); document.write( ". \n" ); document.write( "Of course, we don't normally show 1 times anything. But I just wanted to be clear. \n" ); document.write( ". \n" ); document.write( "Combining we have: \n" ); document.write( ".8(9+x) = .5(9) + x \n" ); document.write( "Multiplying what we have in parentheses \n" ); document.write( "7.2 + .8x = 4.5 + x \n" ); document.write( "Subtracting 4.5 from both sides \n" ); document.write( "2.7 + .8x = x \n" ); document.write( "Subtracting .8x from both sides \n" ); document.write( "2.7 = .2x \n" ); document.write( "Dividing both sides by .2 \n" ); document.write( "13.5 = x \n" ); document.write( "x = 13.5 \n" ); document.write( ". \n" ); document.write( "So this suggests we need to add 13.5 gallons of pure acid to get to an 80% solution. \n" ); document.write( "That seems like an awful lot. But we always check our work, so that's next anyway. \n" ); document.write( ". \n" ); document.write( "If we add 13.5 gallons to 9 gallons, we have 22.5 gallons of solution in total. \n" ); document.write( "If it is 80% acid, then we would have .8(22.5) = 18 gallons of pure acid in the solution. \n" ); document.write( "We started with 4.5 gallons of pure acid and added 13.5 gallons of pure acid = 18. \n" ); document.write( "Done. \n" ); document.write( " |