document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=243391>Question 243391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Train A is traveling at 60 mph and train B is traveling 80 mph. Train A passes a station at 9:10 pm. If train B passes the same station at 9:25 pm, at that time will train B catch up to train A?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178380 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178380\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Do these the easy way:<BR>\n" );
document.write( "In 15 minutes, train A goes 15 miles (60 mph x 1/4 hour)<BR>\n" );
document.write( "Train B gains on train A at 20 mph (80 - 60)<BR>\n" );
document.write( "15 miles/20 mph = 3/4 hour = 45 minutes<BR>\n" );
document.write( "9:25 + 45 = 10:10<BR>\n" );
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