document.write( "Question 243390: 1. One number is 40 more than another. Find the number if the sum is 48.
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document.write( "2. The difference between 6 times a number and 12 equals the sum of the number and thirteen. Find the number.
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document.write( "3. One number exceeds another by 5. If the larger is increased by 5 and the smaller decreased by 8, the larger will be 12 less than twice the smaller. Find the original number.
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Algebra.Com's Answer #178376 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 1) X-Y=40 \n" ); document.write( "X+Y=48 ADD \n" ); document.write( "-------------- \n" ); document.write( "2X=88 \n" ); document.write( "X=88/2 \n" ); document.write( "X=44 ANS. \n" ); document.write( "44-Y=40 \n" ); document.write( "Y=44-40 \n" ); document.write( "Y=4 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "44+4=48 \n" ); document.write( "48=48 \n" ); document.write( "------------------ \n" ); document.write( "2) 6X-12=X+13 \n" ); document.write( "6X-X=13+12 \n" ); document.write( "5X=25 \n" ); document.write( "X=25/5 \n" ); document.write( "X=5 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "6*5-12=5+13 \n" ); document.write( "30-12=18 \n" ); document.write( "18=18 \n" ); document.write( "----------------------- \n" ); document.write( "3) X-Y=5 OR X=Y+5 \n" ); document.write( "(X+5)+12=2(Y-8) \n" ); document.write( "Y+5+5+12=2Y-16 \n" ); document.write( "Y-2Y=-16-5-5-12 \n" ); document.write( "-Y=-38 \n" ); document.write( "Y=38 ANS. \n" ); document.write( "X-38=5 \n" ); document.write( "X=5+38 \n" ); document.write( "X=43 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "43+5+12=2(38-8) \n" ); document.write( "60=2*30 \n" ); document.write( "60=60 \n" ); document.write( " \n" ); document.write( " |