document.write( "Question 243390: 1. One number is 40 more than another. Find the number if the sum is 48.
\n" ); document.write( "2. The difference between 6 times a number and 12 equals the sum of the number and thirteen. Find the number.
\n" ); document.write( "3. One number exceeds another by 5. If the larger is increased by 5 and the smaller decreased by 8, the larger will be 12 less than twice the smaller. Find the original number.
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Algebra.Com's Answer #178376 by checkley77(12844)\"\" \"About 
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1) X-Y=40
\n" ); document.write( "X+Y=48 ADD
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\n" ); document.write( "2X=88
\n" ); document.write( "X=88/2
\n" ); document.write( "X=44 ANS.
\n" ); document.write( "44-Y=40
\n" ); document.write( "Y=44-40
\n" ); document.write( "Y=4 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "44+4=48
\n" ); document.write( "48=48
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\n" ); document.write( "2) 6X-12=X+13
\n" ); document.write( "6X-X=13+12
\n" ); document.write( "5X=25
\n" ); document.write( "X=25/5
\n" ); document.write( "X=5 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "6*5-12=5+13
\n" ); document.write( "30-12=18
\n" ); document.write( "18=18
\n" ); document.write( "-----------------------
\n" ); document.write( "3) X-Y=5 OR X=Y+5
\n" ); document.write( "(X+5)+12=2(Y-8)
\n" ); document.write( "Y+5+5+12=2Y-16
\n" ); document.write( "Y-2Y=-16-5-5-12
\n" ); document.write( "-Y=-38
\n" ); document.write( "Y=38 ANS.
\n" ); document.write( "X-38=5
\n" ); document.write( "X=5+38
\n" ); document.write( "X=43 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "43+5+12=2(38-8)
\n" ); document.write( "60=2*30
\n" ); document.write( "60=60
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