document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=243363>Question 243363</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Finding the radius of a circle using 2A=23 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178342 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178342\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming you mean 2A = 2*Area = 23, then we can proceed.<BR>\n" );
document.write( "A = 23/2 = 11.5<BR>\n" );
document.write( "A = pi*r^2<BR>\n" );
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document.write( "If a=b and b=c, then a=c.  So we can substitute:<BR>\n" );
document.write( "pi*r^2 = 11.5<BR>\n" );
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document.write( "Dividing both sides by pi<BR>\n" );
document.write( "r^2 = 3.66<BR>\n" );
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document.write( "Take the square root (sqrt) of both sides to arrive at the answer<BR>\n" );
document.write( "r = sqrt(3.66) = 1.91 </SPAN>\n" );
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