document.write( "Question 243339: Colin invested 10,000, part at 14% and part at 17%. If the total interest at the end of the year is 1,490, how much did he invest at 14%? \n" ); document.write( "
Algebra.Com's Answer #178287 by checkley77(12844)\"\" \"About 
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.14x+.17(10,000-x)=1,490
\n" ); document.write( ".14x+1,700-.17x=1,490
\n" ); document.write( "-.03x=1,490-1,700
\n" ); document.write( "-.03x=-210
\n" ); document.write( "x=210/.03
\n" ); document.write( "x=$7,000 invested @ 14%.
\n" ); document.write( "10,000-7,000=3,000 invested @ 17% Proof:
\n" ); document.write( ".14*7,000+.17*3,000=1,490
\n" ); document.write( "980+510=1,490
\n" ); document.write( "1,490=1,490
\n" ); document.write( "
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