document.write( "Question 243339: Colin invested 10,000, part at 14% and part at 17%. If the total interest at the end of the year is 1,490, how much did he invest at 14%? \n" ); document.write( "
Algebra.Com's Answer #178287 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .14x+.17(10,000-x)=1,490 \n" ); document.write( ".14x+1,700-.17x=1,490 \n" ); document.write( "-.03x=1,490-1,700 \n" ); document.write( "-.03x=-210 \n" ); document.write( "x=210/.03 \n" ); document.write( "x=$7,000 invested @ 14%. \n" ); document.write( "10,000-7,000=3,000 invested @ 17% Proof: \n" ); document.write( ".14*7,000+.17*3,000=1,490 \n" ); document.write( "980+510=1,490 \n" ); document.write( "1,490=1,490 \n" ); document.write( " |