document.write( "Question 243328: I need help with writing an equation of the line containg the given point and perpendicular to the given line.
\n" ); document.write( "(7,9),6x+y=3
\n" ); document.write( "Can anyone help please? \n" ); document.write( "
Algebra.Com's Answer #178258 by nerdybill(7384)\"\" \"About 
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I need help with writing an equation of the line containg the given point and perpendicular to the given line.
\n" ); document.write( "(7,9),6x+y=3
\n" ); document.write( ".
\n" ); document.write( "First, we find the slope of:
\n" ); document.write( "6x+y=3
\n" ); document.write( "To do so, place it in the \"slope-intercept\" form:
\n" ); document.write( "y = mx + b
\n" ); document.write( "where
\n" ); document.write( "m is the slope
\n" ); document.write( "b is the y-intercept
\n" ); document.write( ".
\n" ); document.write( "6x+y=3
\n" ); document.write( "y = -6x + 3
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\n" ); document.write( "From inspection, then, the slope is -6.
\n" ); document.write( "Our new line, to be perpendicular, has to be the \"negative reciprocal\"
\n" ); document.write( "That is, our slope m has to be:
\n" ); document.write( "-6(m) = -1
\n" ); document.write( "m = 1/6 (this is the slope of our new line)
\n" ); document.write( "That, along with the given point (7,9) is plugged into the \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x-x1)
\n" ); document.write( "y - 9 = (1/6)(x - 7)
\n" ); document.write( "y - 9 = (1/6)x - 7/6
\n" ); document.write( "y = (1/6)x - 7/6 + 9
\n" ); document.write( "y = (1/6)x - 7/6 + 54/6
\n" ); document.write( "y = (1/6)x + 47/6 (this is what they are looking for)\r
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