document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=243260>Question 243260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two numbers are in the ration 3:8. If the first number is increased by 4 and the second number is decreased by 6, the resulting numbers are in the ratio of 1:2. Find the original numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178256 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178256\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3x+4):(8x-6)=1:2<BR>\n" );
document.write( "2(3x+4)=(8x-6)<BR>\n" );
document.write( "6x+8=8x-6<BR>\n" );
document.write( "-2x=-14<BR>\n" );
document.write( "x=-14/-2<BR>\n" );
document.write( "x=7<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "(3*7+4):(8*7-6)=1:2<BR>\n" );
document.write( "(21+4):(56-6)=1:2<BR>\n" );
document.write( "25:50=1:2<BR>\n" );
document.write( "1:2=1:2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );