document.write( "Question 243233: solve t^2=9 \n" ); document.write( "
Algebra.Com's Answer #178207 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
Subtract 9 from both sides.
\n" ); document.write( "\"x%5E2+-9+=+0\"
\n" ); document.write( "I hope you see that you can factor this easily because 9 is a perfect square (3*3), and that you do not need an 'x' value, and that it is -9.
\n" ); document.write( "...
\n" ); document.write( "If you memorized \"x%5E2+-1+=+%28x%2B1%29%28x-1%29\" you can substitute any perfect square for the '1'.
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\n" ); document.write( "So the solution is,
\n" ); document.write( "(x+3)(x-3)=0
\n" ); document.write( "...
\n" ); document.write( "So, x can = 3 or -3.
\n" ); document.write( "That is the same as saying the square root of 9 can be either +3 or - 3, which is true.
\n" ); document.write( "...
\n" ); document.write( "That suggests we could have solved the problem by taking the square root of each side first.
\n" ); document.write( "\"sqrt%28x%5E2%29=sqrt%289%29\"
\n" ); document.write( "...
\n" ); document.write( "The square root of x^2 is simply + or - x.
\n" ); document.write( "The square root of 9 is simply + or - 3.
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