document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=243203>Question 243203</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In any triangle, the sum of the measures of the angles is 180° . In &#916;ABC, &#8738; A is three<BR>\n" );
document.write( "times as large as &#8738; B and also 16° larger than &#8738; C. Find the measure of each angle.<BR>\n" );
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document.write( "In any triangle, the sum of the measures of the angles is 180° . In &#916;ABC, &#8738; A is twice as<BR>\n" );
document.write( "large as &#8738; B. &#8738; B is 4° larger than &#8738; C. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178202 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178202\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The setup of the problem tells us:<BR>\n" );
document.write( "A + B + C = 180<BR>\n" );
document.write( "A = 3B, so B = A/3 <BR>\n" );
document.write( "A = C+16, C = A-16<BR>\n" );
document.write( "Substitute into basic formula:<BR>\n" );
document.write( "A + A/3 + A-16 = 180<BR>\n" );
document.write( "2A + A/3 = 196<BR>\n" );
document.write( "Getting rid of the fractional A is next:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%0D%0A2A+=+%286%2F3%29A%0D%0A ALIGN=MIDDLE  ALT=\"%0D%0A2A+=+%286%2F3%29A%0D%0A\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<BR>\n" );
document.write( "So we have:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%0D%0A%286%2F3%29A+%2B+A%2F3+=+%286%2F3%29A+%2B+%281%2F3%29A+=+%287%2F3%29A+=+196%0D%0A ALIGN=MIDDLE  ALT=\"%0D%0A%286%2F3%29A+%2B+A%2F3+=+%286%2F3%29A+%2B+%281%2F3%29A+=+%287%2F3%29A+=+196%0D%0A\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Which can be simplified by multiplying both sides by 3.<BR>\n" );
document.write( "7A = 3*196 = 588<BR>\n" );
document.write( "Dividing both sides by 7, we have:<BR>\n" );
document.write( "A = 84<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Looking back to the equations we define:<BR>\n" );
document.write( "B = A/3 = 84/3 = 28<BR>\n" );
document.write( "and <BR>\n" );
document.write( "C = A-16 = 68<BR>\n" );
document.write( "...<BR>\n" );
document.write( "To summarize:<BR>\n" );
document.write( "A = 84<BR>\n" );
document.write( "B = 28<BR>\n" );
document.write( "C = 68<BR>\n" );
document.write( "...<BR>\n" );
document.write( "To check your work, check the solution to the fundamental equation.<BR>\n" );
document.write( "Does A + B + C = 180?<BR>\n" );
document.write( "84 + 28 + 68 = 180<BR>\n" );
document.write( "So we have our answer.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Follow these same steps to answer your 2nd question. </SPAN>\n" );
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