document.write( "Question 243183: Graph f(x)=(1/5)x+1 \n" ); document.write( "

Algebra.Com's Answer #178183 by nerdybill(7384) $\"\"$ $\"About$

You can put this solution on YOUR website!
f(x)=(1/5)x+1
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\n" ); document.write( "You can also rewrite it as:
\n" ); document.write( "y=(1/5)x+1
\n" ); document.write( "Now, it is in the more familiar \"slope-intercept\" form:
\n" ); document.write( "y = mx + b
\n" ); document.write( "where
\n" ); document.write( "m is the slope (rise/run)
\n" ); document.write( "b is the y-intercept at (0,b)
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc

Equation $\"-0.2+x+%2B+1+y+=+1\"$ describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is $\"-a%2Fb+=+--0.2%2F1\"$ .

X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 1/-0.2 = -5.
Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 1/1 = 1.
Slope is --0.2/1 = 0.2.
Equation in slope-intercept form: y=0.2*x+1.

$\"graph%28+500%2C+500%2C+-5-8%2C+-5%2B8%2C+1-8%2C+1%2B8%2C+0.2%2Ax%2B1+%29+\"$ \n" ); document.write( "

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