document.write( "Question 243145: A beaker contains a solution that is 15% alcohol. In another beaker is a solution that is 40% alcohol. How mcuh of each should be mixed to obtain 9 L of solution that is 25% alcohol? \n" ); document.write( "
Algebra.Com's Answer #178157 by checkley77(12844)\"\" \"About 
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.40x+.15(9-x)=.25*9
\n" ); document.write( ".40x+1.35-.15x=2.25
\n" ); document.write( ".25x=2.25-1.35
\n" ); document.write( ".25x=.9
\n" ); document.write( "x=.9/.25
\n" ); document.write( "x=3.6 L of 40% solution is used.
\n" ); document.write( "9-3.6=5.4 L of 15% solution is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".40*3.6+.15*5.4=2.25
\n" ); document.write( "1.44+.81=2.25
\n" ); document.write( "2.25=2.25
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