document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=243115>Question 243115</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factorise;<BR>\n" );
document.write( "axy-ay+ax-a\r<BR>\n" );
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document.write( "I think I've got the correct answer;<BR>\n" );
document.write( "(ay+a)(x-1)<BR>\n" );
document.write( "but I kind of just did trial and error. I was wondering if there's a faster or more straight forward way of getting there?<BR>\n" );
document.write( "Thanks SO much again (you guys are AWESOME!)<BR>\n" );
document.write( "manda </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178137 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178137\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello Manda, <BR>\n" );
document.write( "You are correct. Good going! We can go one more step. (See below)<BR>\n" );
document.write( "Since I didn't see how you did it I couldn't say if your way was fastest. Here's the way I'd do it. I see in the first two terms a common thread of ay, so we could pull that out like:<BR>\n" );
document.write( "ay(x-1) <BR>\n" );
document.write( "Now notice in the last two terms the common thread is a, so we can rewrite that:<BR>\n" );
document.write( "a(x-1) Notice that these two have (x-1) therefore we can write this as:<BR>\n" );
document.write( "(ay+a)(x-1) We could go one more step and write it as:<BR>\n" );
document.write( "a(y+1)(x-1) Multiply all that out and we should arrive at the original expression. <BR>\n" );
document.write( "RJ Toftness<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
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