document.write( "Question 31090: Question: if 2x-4y=-2 and 3x-2y=3, then 2y+x= \r
\n" ); document.write( "\n" ); document.write( "I need help solvng one equation in terms of the other to answer this question. \r
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Algebra.Com's Answer #17813 by Cintchr(481)\"\" \"About 
You can put this solution on YOUR website!
\"+2x-4y=-2+\" and \"+3x-2y=3+\" then \"+2y%2Bx=z+\"
\n" ); document.write( "Using the first equation ... solve for x
\n" ); document.write( "\"+2x-4y=-2+\"
\n" ); document.write( "\"+2x=4y-2+\" divide all parts by 2
\n" ); document.write( "\"+x=2y-1+\" substitute this value into the 2nd equation
\n" ); document.write( "\"+3x-2y=3+\"
\n" ); document.write( "\"+3%282y-1%29-2y=3+\" solve for y
\n" ); document.write( "\"+6y-3-2y=3+\"
\n" ); document.write( "\"+4y-3=3+\"
\n" ); document.write( "\"+4y=6\"
\n" ); document.write( "\"+y=6%2F4+\" or \"+y=3%2F2+\" substitute this back into the first eq.
\n" ); document.write( "\"+x=2y-1+\"
\n" ); document.write( "\"+x=2%283%2F2%29-1+\" solve for x
\n" ); document.write( "\"+x=3-1+\"
\n" ); document.write( "\"+x=2+\" substitute x and y into the third equation
\n" ); document.write( "\"+2y%2Bx=z+\" and \"+x=2+\" and \"+y=3%2F2+\"
\n" ); document.write( "\"+2%283%2F2%29+%2B+2+=z+\"
\n" ); document.write( "\"+3+%2B+2+=z+\"
\n" ); document.write( "\"+5+=+z+\"
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